9.72 g of potassium chloride is dissolved in 30g of water at 70 degree celcius.Calculate the solubility of potassium chloride at that temperature
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Answered by
3
Answer:
100/30*9.72
=32.4 kg
This is the answer but you write in process.
Answered by
7
Answer: The solubility of potassium chloride at the given temperature is 32.4 g/100 g
Explanation:
Solubility is defined as the amount of solute that can be dissolved in 100 grams of solvent.
We are given:
Amount of potassium chloride dissolved in 30 grams of water = 9.72 g
To calculate the mass of potassium chloride that can be dissolved in 100 g of water, we use unitary method:
In 30 grams of water, amount of KCl dissolved is 9.72 grams
So, in 100 grams of water, amount of KCl dissolved will be = \frac{9.72g}{30g}\times 100=32.4g
30g
9.72g
×100=32.4g
Hence, the solubility of potassium chloride at the given temperature is 32.4 g/100 g
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