9.8 g H2SO4 প্রশমিত করতে কত গ্ৰাম NaOH প্রয়োজন
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8 g NaOH প্রয়োজন 9.8 g H2SO4 কে প্রশমিত করতে।
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10 g of NaOH (molar mass 40 g/mol) = 40g/mol 10g =0.25mole
2NaOH+H2SO4 →Na2SO4+2H2O
0.25 mole of NaOH will react with 20.25
=0.125 mole of H2SO4
So, the no. of moles of H2SO4 require to neutralize 10 g of NaOH is 0.125 mole.
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