Question

9.8 gm of h2so4 is present in 2lt of solution. The molarity of solution is

Answer 1

Answer:

Molarity :

It is defined as number of moles of solute present in unit volume of solution in litre.

M = n / V

n = M / MM

i.e. No. of moles = Given mass / Molar mass

Given :

M = 9.8 g

V = 2 L

We know :

Molar mass of H₂SO₄ is 98 g / mol

n = 9.8 / 98

n = 1 / 10

n = 0.1 moles

Now :

M = 0.1 / 2

M = 0.05 M

Therefore , Molarity of the solution is 0.05 M.