Question

9.80 g of KClO3 on heating produces 3.84 g of oxygen and the residue KCl left behind weighs 5.92 g. Show that

whether this experiment illustrates the law of conservation of mass. Explain your answer. pls don't spam or answer will be reported. pls hast.​

Answer 1

Answer:Answer : This reaction follow 'Law of conservation of mass'.

Solution : Given,

Mass of potassium chlorate = 4.90 g

Mass of oxygen = 1.92 g

Molar mass of oxygen = 32 g/mole

Molar mass of potassium chlorate = 122.55 g/mole

Molar mass of potassium chloride = 74.55 g/mole

The balanced chemical reaction is,

2KClO_3 \overset{\Delta}{\rightarrow}2KCl+3O_22KClO

3

→

Δ

2KCl+3O

2

Step 1 : First we have to calculate the moles of potassium chlorate.

\text{ Moles of } KClO_3=\frac{\text{ mass of } KClO_3}{\text{ molar mass of } KClO_3} Moles of KClO

3

=

molar mass of KClO

3

mass of KClO

3

= \frac{4.9g}{122.55g/mole}=0.0399moles

122.55g/mole

4.9g

=0.0399moles

Step 2 : Now we have to calculate mass of O_2O

2

.

From the balanced chemical reaction, we conclude that

2 moles of potassium chlorate produced 3 moles of oxygen

and 0.0399 moles of potassium chlorate produced [\frac{3moles}{2moles}\times 0.0399moles][

2moles

3moles

×0.0399moles] moles of oxygen

The moles of oxygen produced = 0.05985 moles

The mass of oxygen produced = Number of moles of oxygen × Molar mass of oxygen = 0.05985 moles × 32 g/mole = 1.9152 g

Step 3 : Now we have to calculate the mass of KCl.

From the balanced chemical reaction, we conclude that

2 moles of potassium chlorate produced 2 moles of KCl

and 0.0399 moles of potassium chlorate produced [\frac{2moles}{2moles}\times 0.0399moles][

2moles

2moles

×0.0399moles] moles of KCl

The moles of KCl produced = 0.0399 moles

The mass of KCl produced = Number of moles of KCl × Molar mass of KCl = 0.0399 moles × 74.55 g/mole = 2.974 g

According to the 'Law of conservation of mass', the mass of reactant side is equal to the mass of product side.

The mass of reactant side = mass of potassium chlorate = 4.90 g

The mass of product side = mass of KCl + mass of oxygen = (1.9152 + 2.974)g = 4.889 g ≈ 4.9 g

Thus, we conclude that the mass of reactant is equal to the mass of product.

Hence, this reaction follow the 'Law of conservation of mass'.

Explanation: