Question

9. A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time
(i) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of a
lov:
pole which casts a shadow 5m long.​

Answer 1

Answer:

Step-by-step explanation:

5m 60 cm/10 m 50 cm = 3m 20 cm/x i) x = Length of shadow cast = 320(105)/560 = 60 cm. i) x = Length of shadow cast = 320(105)/560 = 60 cm.

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Answer 2

$(i) \frac{x_{!}}{x_{1}} = \frac{x_{2}}{y_{2}}$

$⇒ \frac{5.6}{3.2} = \frac{10.5}{y_{2}}$

$⇒y_{2}=6 cm$

$(ii) \frac{x_{1}}{y_{1}} = \frac{x_{3}}{y_{3}}$

$⇒ \frac{5.6}{3.2} = \frac{x_{3}}{5}$

$⇒x_3=8.75 m$