(9, a), (6, 7), (2, 3) are the coordinates of the vertices of a triangle. If the area of the
triangle is 10, find a.
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Plot the points in a rough diagram and take them in order.
Let the vertices be A(1,2),B(−3,4) and C(−5,−6)
Now the area of △ABC is
=
2
1
{(x
1
y
2
+x
2
y
3
+x
3
y
1
)−(x
2
y
1
+x
3
y
2
+x
1
y
3
)}
=
2
1
{(4+18−10)−(−6−20−6)}
=
2
1
(12+32)=22 sq.units.
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