9(a-b)² - 4(2a-b) - 13
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bonjour!
here is your answer
Given 9(2a – b)2 – 4(2a – b) – 13
Put (2a – b) = k
Hence 9(2a – b)2 – 4(2a – b) – 13 = 9k2 – 4k – 13
= 9k2 – 13k + 9k – 13
= k(9k – 13) + 1(9k – 13)
= (9k – 13)(k + 1)
= [9(2a – b) – 13)[(2a – b) + 1]
= [18a – 9b – 13)[2a – b + 1]
hope it helps
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Anmol18125:
why u put 2 (a-d) =k
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