Question

9. A block of mass 250 g slides down an incline of
inclination 37° with a uniform speed. Find the work done
against the friction as the block slides through 1.0 m.​

Answer 1

Answer:

$components \: of \: acceleration \\ = g sin37 \\ \frac{3g}{5} = \frac{6m}{s {}^{2} } \\ f = ma \\ f = 0.25 \times 6 \\ f = 1.5newton \\ work \: done \: = 1.5 \times 1 = 1.5joules$