Question

9. A block of mass 4kg is placed in contact with
the front vertical surface of a lorry. The
coefficient of friction between the vertical
surface and block is 0.8. The lorry is moving
with an acceleration of 15 m/s2 (g = TOms).
The force of friction between lorry and block is
1) 48N 2) 24 N 3) 40 N 4) zero​

Answer 1

Answer:

answer is zero

Explanation:

because the angle between them is 90 %

here is the formula to calculate the friction

Friction force = coefficient of friction * mass * gravity * cos (angle)

Ff= 0.8 * 4 Kg * 10 m/s2 * cos (90)

Ff = 0.8*40 * 0

cos (90) = 0

so the friction force will be zero