9. A cylindrical tank of radius 80 cm contains water to a
depth of 2 m. What is the total area of wetted surface?
Answers
Answered by
4
Answer:
Given, 2r=7
⇒r=7/2;h=4
Area of wetted surface = CSA of cylinder ABCD + Area of base (Circle)
=2πrh=πr
2
=πr(2h+r)
=
7
22
×
2
7
(8+3.5)
=11×11.5=126.5 sq. m
Answered by
0
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• Given:-
Cylindrical tank has radius of 80cm
Depth of the cylindrical tank is 2cn
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• To Find:-
Area of Wetted surface
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• Solution:-
We need to find the Total Surface Area of the cylindrical tank.
Hence,
T.S.A of cylindrical tank = Area of base of tank + C.S.A of tank
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Therefore,
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Area of wetted surface will be
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Therefore, the area of wetted surface is 21100.8 cm²
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