Question

9. A heap of wheat is in the form of a cone whose diameter is 10,5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain Tinta area of the canvas required.
​

Answer 1

Answer:

Given:

⇒Diameter =10.5 m

⇒radius =r =5.25 m

⇒height =3 m

⇒volume =

3

1

πr

2

h

⇒Volume=(

3

1

×

7

22

×5.25×5.25×3) m

3

⇒Volume=86.625m

3

For slant height:

⇒l

2

=h

2

+r

2

=3

2

+(5.25)

2

=9+27.5625=36.5625

⇒6.0467 m(approx)

Canvas needed to protect wheat from rain

Therefore, curved surface area=πrl

=(227×5.25×6.0467) m

2

=99.77 m

2

(approx)

Answer 2

Answer:

Step-by-step explanation:

Given:

⇒Diameter =10.5 m

⇒radius =r =5.25 m

⇒height =3 m

⇒volume =

3

1

​

πr

2

h

⇒Volume=(

3

1

​

×

7

22

​

×5.25×5.25×3) m

3

⇒Volume=86.625m

3

For slant height:

⇒l

2

=h

2

+r

2

=3

2

+(5.25)

2

=9+27.5625=36.5625

⇒6.0467 m(approx)

Canvas needed to protect wheat from rain

Therefore, curved surface area=πrl

=(227×5.25×6.0467) m

2

=99.77 m

2

(approx)