Question

9. A jet of water 50 mm in diameter
strikes on a fixed flat plate normally
with a velocity of 25 m/s. The force
exerted by jet is​

Answer 1

Answer:

i) Diameter of jet, d = 50mm = 0.075mm

ii) Area, a=π4d2=π4(0.075)2=0.004417m2

iiii) Velocity of jet, v = 20m/s

The force exerted by the jet of water on a stationary plate is given by,

F=ρav2

F=1000×0.004417×202=1766.8N