Question

9. A man travels 24 miles to the east and turns north and again travels 10 miles towards the north. Find the shortest distance from the starting point to the end.

Answer 1

Answer:

We have

Towards North=24m

Towards East=10m

Using Pythagoras Theorem,

(Hypotenuse)

2

=(base)

2

+(height)

2

=(10)

2

+(24)

2

=100+576

=676

=(26)

2

Starting point =

(Hypotenuse)

2

=

(26)

2

=26m

Hence, this is answer.

Step-by-step explanation:

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Answer 2

Solution:-

Let man travel distance in East (OB) = 24 miles

And man travel towards North (AB) = 10 miles

Simply , we can observe from the figure we have to find AO distance and this is the shortest distance

So,

By applying Pythagoras theorem:-

$\large\sf \purple {AO^{2} = {AB}^{2} + {OB}^{2}}\\ \purple{ {AO }^{2} = {10}^{2} + {24}^{2} } \\ \purple{ {AO}^{2} = 100 + 576} \\ \purple{AO = √676} \\ \purple{AO = 26}$

$\therefore\mathbf\orange{\underline {The \: shortest \: distance \: from \: the}}$

$\mathbf\orange{\underline{starting \: point \: to \: the \: end \: is \: 26 \: miles}}$