Question

9.
A metal in its dipositive state has the electronic
configuration 2, 8, 14 and has the atomic weight
equal to 56. Number of neutrons in its nucleus
would be :-
(1) 30 (2) 32 (3) 34 (4) 28

Answer 1

Answer:

(2) 32

as no. of electrons = the no. of protons so, protons =electrons=2+8+14=24

and mass of atom is protons+neutrons=56

24+neutrons=56

neutrons=56-24

neutrons=32

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Answer 2

Answer:

(1) 30

Explanation:

Metal in its dipositive state = M²^+

Electronic configuration of metal ion M²^+ =2,8,14

therefore, Atomic No.(Z) (No. of proton) = 24+2 = 26

No. of electron = 26

Atomic weight = 56 (given)

We know

Mass no. = No. of neutrons + atomic no.(no.of protons)

No. of neutrons = Mass no. - atomic no.

= 56 - 26

= 30

Hence, no. of neutrons would be 30