Question

9. A number increased by 137-% gives 33, then the
number is
(a) 16
(6) 24
(c) 20
(d) 28
​

Answer 1

Answer:

Let the required number be x.

Atq,

$\: \: \: \: \: \: \: \: x + 137\% \: of \: x = 33 \\ = > x + \frac{137}{100} \times x = 33 \\ = > x + \frac{137x}{100} = 33 \\ = > \frac{100x + 137x}{100} = 33 \\ = > \frac{237x}{100} = 33 \\ = > 237x = 100 \times 33 \\ = > x = \frac{100 \times 33}{237} \\ = > x = \frac{100 \times 11}{79 } \\ = > x = \frac{1100}{79}$

Hence, the required number = $\frac{1100}{79}$