Question

9. A piece of wire is in the form of a rectangle with dimensions 24 cm and 20 cm. It is reshaped and bent into the form of a circle. Calculate the radius of this circle.​

Answer 1

$24 \times 20 = \frac{22}{7} {r}^{2}$

$\frac{24 \times 20 \times 7}{22} = {r}^{2}$

$\frac{12 \times 20 \times 7}{11} = {r}^{2}$

$r = \sqrt{ \frac{12 \times 20 \times 7}{11} }$

HOPE HELPFUL

Answer 2

Given that side of the square is 22 cm

Perimeter of the square =4a

-4x22

-88 cm

As the same wire is used to form a circle then both will have same perimeter.

Perimeter of circle = Perimeter of square

⇒ 2mr-88

⇒2x

7

22

r=88

88x7

⇒r-14 cm

Hence radius of the circle is 14 cm.