Question

9
A pole 65 feet long rests against a wall.

(i) If its top end touches the wall at a height of 63 feet, how far is its foot from the
wall?
(ii) If the foot of the pole is moved 17 feet away from the first position, by how much
does the pole slide down?

Answer 1

Answer:

It is sixteen foot from the wall.

θ = $cos^{-1}33/63$

Step-by-step explanation:

It is given that a pole 65 feet long rests against a wall.

If its top end touches the wall at a height of $63$ feet, we need to determine how far is its foot from the wall.

(i) It is a case of right angles triangle.

H=65 feet

P=63 feet

Base =?

Using pythagorean theorem

$65^{2} =63^{2}+B^{2}$

Solving

$B^{2} =256$

$B=16$ feet.

It is sixteen foot from the wall.

(ii) If the foot of the pole is moved 17 feet away,

$B=16+17=33$feet

$H=65$feet

cos θ $=33/65$

θ = $cos^{-1}33/63$

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