Question

9. A road roller takes 750 complete revolutions to move
once over to level a road. Find the area of the road if the
diameter of a road roller is 84 cm and length is 1 m.
​

Answer 1

Answer:

Diameter = 84cm

Radius = d/2 = 42cm

Height (length) = 1m = 100cm

CSA = 2πrh

= 2×22/7×42×100

=26400

Area of the road = CSA×No of revolution

= 26400×750

= 19800000cm^

In meter square

19800000/10000

=1980m^

Answer 2

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In one revolution, the roller will cover an area equal to its lateral surface area

Thus, in 1 revolution, area of the road covered=2 rok

22 x 42 cm IN m42 = 2x mx1 m100

264

m2

100

In 750 revolutions, area of the road covered

264

750x

m2

100

= 1980 m2