Math, asked by harshuti, 1 year ago

(y cube minus 5y square)÷y×(y-1)

Answers

Answered by lucky783
1
y^2(y-5)/y(y-1)
y(y-5)/y-1
y^2-5y/y-1
Answered by rajeev378
8
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Here is your answer
 {y}^{3} - 5 {y}^{2} \div y(y - 1) \\ = \frac{y( {y}^{2} - 5y) }{y(y - 1)} \\<br />= \frac{ {y}^{2} - 5y }{y - 1}

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