9 a square b square (3x-24) ÷27ab(x-2)
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Solution :
[9a²b²(3x-24)]/[27ab(x-2)]
= [9ab*ab*3(x-8)]/[27ab(x-2)]
= [ 27ab*ab(x-8)]/[27ab(x-2)]
After cancellation, we get
= [ab(x-8)]/(x-2)
••••
[9a²b²(3x-24)]/[27ab(x-2)]
= [9ab*ab*3(x-8)]/[27ab(x-2)]
= [ 27ab*ab(x-8)]/[27ab(x-2)]
After cancellation, we get
= [ab(x-8)]/(x-2)
••••
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