Question

9. A student goes to 4 meters to east and turns at right angle and travels 3 2
meters distance. The displacement of the boy from its initial position to
final position is
7m
5m
lm
25 m​

Answer 1

Answer:

Explanation:

option b

Answer 2

Concept:

Net displacement can be find out by summation of all displacements

Given:

First student travels 4 metres in east

Then took a right angle turn and travel 3 metres

Find:

Net displacement from initial to final position

Solution:

Displacement in east direction = 4 metres

then travel 3 metres after taking right angle turn

So the net displacement from initial to final position can be find out by adding the two vectors.

Net displacement = (4² + 3² + (2×4×3×cosα) )

The value of α is 90° here as student take right angle turn here

Net displacement = √(4² + 3² + (2×4×3×cos90°) )

Net displacement = √(4² + 3² + (2×4×3×0) )

Net displacement = √(4² + 3² + 0 )

Net displacement = √(16 + 9 + 0 )

Net displacement = √25

Net displacement = 5 metres

Hence the student travel a displacement of 5 metres.

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