Question

9. A uniform metre rule rests horizontally on a knife
= 1-0 + 1-0 = 2-0 Nm
edge at the 60 cm mark when a mass of 10 g is
suspended from one end. Draw a diagram of the
arrangement.
(a) At which end must this mass be suspended ?
(b) What is the mass of the rule ?






answer fast and dont give usless answer ir else ill report that particular answer......
the best one ill mark as brainlist......​

Answer 1

Explanation:

Let M gram be the mass of the rule. Since density of the rule is uniform, its weight Mg will act at its middle point i.e., at the 50 cm mark

The weight of the rule produces an anti-clockwise moment about the knife-edge O. In order to balance it, 10 gram mass is to be suspended at the end B, to produce a clockwise moment.

From the principle of moments,

Anti-clockwise moment = Clockwise moment

Mg × (60 – 50) = 10 g × (100-60)

or Mg × 10 = 10 g × 40

∴ M = 40 gram

plzz follow me palak