Question

9. ABCD is a kite. If angleBCD = 40°, find (a) angleBDC (b) angleABC.​

Answer 1

Answer:

(a) BDC = 70°

and,

(b) ABC = 140°

Step-by-step explanation:

Solution:-

Given,

ABCD is a kite

∠BCD = 40°

(a)

∠ABC + ∠BCD = 180°

=> ∠ABC + 40° = 180°

=> ∠ ABC = 180° - 40°

=> ∠ABC = 140°

(b)

∠BDC = 1/2 ∠ADC

1

∠BDC = ── ∠ABC

2

( kite opposite angels are equal so

∠ADC =∠ABC)

1

∠BDC = = ── ×140°

2

=> ∠BDC = 70°