Question

9. ABCD is a parallelogram and E is the
midpoint of BC (Fig. 11.19). The side DC
is extended such that it meets AE, when
extended, at F. Prove that DF = 2DC.

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Triangle ABE and Triangle FCE are congruent by ASA rule

So AB = CF by CPCT

But AB = DC (ABCD is llgm)

Therefore DC =CF

DC+CF =DF

DC+DC=DF

2DC=DF

Hence Proved