Question

9. ABCD is a parallelogram. If P, Q, R and S are the midpoints of the sides AB, BC, CD and DA respectively, then
prove that PQRS is also a parallelogram.​

Answer 1

Answer:

For this question we can use the theorem that a line joining the mid points of 2 sides of the triangle is parallel to the third side and equal to half of its length.

P and Q are mid-points of the sides AB and BC of triangle ABC.

=> PQ is parallel to side AC of triangle ABC and of length = (1/2)AC.

R and S are mid-points of the sides CD and DA of triangle ACD => RS is parallel to side AC of triangle ACD and of length = (1/2)AC

=> PQ and RS which are the opposite sides of the quadrilateral PQRS are of equal length and both being parallel to AC are parallel to each other. => quadrilateral PQRS is a parallelogram.Also since, triangle(PQB)~triangle (ABC)

ar(PQB)/ar(ABC) = PQ2/BC2 = 1/4

area(PQB) = 1/4 * ar(ABC)

Similarly, ar(SDR) = 1/4*ar(ADC)

ar(CRQ) = 1/4*ar(CDB)

ar(ASP) = 1/4*(ADB)

ar(PQRS) = ar(ABCD) - ar(PQB) - ar(SDR) - ar(CRQ) - ar(ASP)

ar(PQRS) = ar(ABCD) - 1/4* (ar(ABC) +ar(ADC)+ar(CDB)+ar(ADB))

ar(PQRS) = ar(ABCD) - 1/4* (2* ar(ABCD))

ar(PQRS) =1/2 ar(ABCD)

Hence, proved