Question

9.An object of 7 cm height is placed at a distance of 12 cm from a convex lens of focal
length 8 cm, find the position nature and height of the image.​

Answer 1

Answer:

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Answer 2

Answer:

Given: U= -12cm, f=+8 cm

Putting these values in the lens formula.

$\frac{1}{v}\:-\: \frac{1}{u}\:=\: \frac{1}{f} \:\: we\:get,\:\frac{1}{v}\:-\: \frac{1}{-12}\:=\: \frac{1}{f}\\\\\frac{1}{v}\:=\: \frac{1}{8}\:-\: \frac{1}{12}\:\:\:thus,\:\frac{1}{v}\:=\:\frac{1}{24}\\V\:=\:+24\:cm\\\\Magnification,\:m\:=\:\frac{v}{u}\:=\:\frac{h1}{h2}\\\\\\m\:=\:\frac{24}{-12}\:=\:\frac{h2}{7},\\\\Thus,\:h2\:=\:-14cm$

Hope it helps you :)