Question

9. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is ₹ 1,600, find the marked price
- need verified answer with full explanation

Answer 1

Answer:

$\huge\blue\star\underbrace\mathtt{\underline{\underline\red{Answer}}}$

$\bold\red{Given:-}$

Discount percentage:- 20%

Sale price:- 1600

$\bold\pink{To \:find :-}$

Marked price.

$\bold\orange{Solution:-}$

Let the marked price= ₹100

$\bold{Discount}$= 20% of ₹100

➡₹$\sf\large\ \frac{20}{100}$×100 =₹20

Sale price: ₹(100-20)=₹80

If sale price is ₹80, then marked price= ₹100.

If sale price is ₹1600, then marked price

➡₹$\sf\large\ \frac{100}{80}$

$\dashrightarrow\: \underline{\boxed{\bf{\blue{=RS.2000}}}}$

Answer 2

Question :-

• Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is ₹ 1,600 . Then find the marked price .

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Answer :-

• Marked Price = ₹ 2,000 .

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Explanation :-

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Given :-

• Discount = 20 %
• Amount = ₹ 1,600

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To Find :-

• Marked Price = ?

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Solution :-

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Let the Marked Price be x .

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✪ $\sf\red{Discount\:\%}\large\sf\:=\:{\frac{Discount}{Marked\:Price}}=100$

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• Now, let's substitute -----

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$\longmapsto \sf{20 \: x = \frac{x - 1600}{x} \times 100 } \\ \\ \longmapsto \sf{20 \: x = 100 \: ( \: x - 1600 \: )} \\ \\ \longmapsto \sf{20 \: x = 100 \: x - 1,60,000} \\ \\ \longmapsto \sf{20 \: x - 100 \: x = - 1,60,000} \\ \\ \longmapsto \sf{ - 80 \: x = - 1,60,000} \\ \\ \longmapsto \sf{80 \: x = 1,60,000} \\ \\ \longmapsto \sf{x = \frac{1,60,000}{80} } \\ \\ \longmapsto \tt\red{x = 2,000}$

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Hence :-

• Marked Price = ₹ 2,000 .

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