9 boards are stacked on top of each other. the thickness of each board is 3 2/3 cm. How high is the sack?
Answers
Answer:
Answer:
Given,
Age of 'D' = 38 years
Age of 'C' = Half the Age of D
Age of 'B' = Trice the age of 'C'
Age of 'A' = 20 years less than Age of 'B'.
To Find :-
Age of 'B'.
Solution :-
Given,
1)Age of 'C' = Half the Age of 'D'
Age of 'D' = 38 Years.
\sf\implies Age of 'C' = \dfrac{38 Years}{2}⟹Ageof
′
C
′
=
2
38Years
Age of 'C' = 19 years.
\sf\therefore Age of C = 19Years∴AgeofC=19Years
2) Age of 'B' = Thrice the Age of 'C'
Age of 'C' = 19 Years
\sf\implies Age of 'B' = 3 \times 19 Years⟹Ageof
′
B
′
=3×19Years
Age of 'B' 57 Years
\sf\therefore Age of 'B' = 57 Years∴Ageof
′
B
′
=57Years
3) Age of 'A' = 20 years less than Age of 'B'
Age of 'B' = 57Years
Age of 'A' = 57Years - 20Years
Age of 'A' = 37Years
\sf\therefore Required is Age of 'B' = 57years∴RequiredisAgeof
′
B
′
=57years
Answer:
The thickness of each board is 3 2 3 cm. How high is the stack? Hence, the height of the stack is 33 cm.
hope this helps you please mark me as Brainliest