Question

9. Chandrika's mother was 4 times her age 10 years ago. She will be twice as old as Chandrika 10
years from now. What is the present age of Chandrika's mother?​

Answer 1

Given: Chandrika's mother was$4$ times of her age$10$ years ago. She will be twice as old as Chandrika's age$10$  years from now.

We have to find the present age of Chandrika's mother.

We are using the concept of ages.

Let assume Chandrika's mother's age now is $=$$x$,

              $10$ yrs ago her age$=$ $x-10$

              $10$ yr hence her age$=$ $x+10$

Then,

$10$ yr. ago Chandrika's age will be $\frac{x-10}{4} yr.$

 And $10$ yr. hence her age will be $\frac{X+10}{2} yr.$

we have

=> $\frac{x-10}{4} +20=\frac{x+10}{2}$

$=>x-10+80=2x+20\\=>x=50$

Hence, The present age of Chandrika's mother is$50$ yrs.

Answer 2

Given:

We have given that Chandrika's mother was times of her age years ago. She will be twice as old as Chandrika's age years from now.

Find:

We have to find the present age of Chandrika's mother.

Solution:

We are using the concept of ages.

Let assume Chandrika's mother's age now is,

           10 yrs ago her age $=x-10$

            10 yr hence her age $=x+10$

Further, we solve

10 yr. ago Chandrika's age will be $\frac{x-10}{4} yr$

And 10 yr. hence her age will be $=\frac{x+10}{2} yr$

we have

 $\frac{x-10}{4} +20=\frac{x+10}{2}$

$x-10+80=2x+20\\x=50$

Hence, We get the present age of Chandrika's mother that is 50 yrs.