Math, asked by reetika9, 3 months ago

The ages of Seeta and Meeta are in the ratio 5: 7. Ten years hence the
ratio of their ages will be 7: 9. Find their present ages.​

Answers

Answered by berbet7
0

Answer:

Step-by-step explanation:

SOLN

GIVEN

AGE RATIO OF SEETA AND MEETA 5:7

LET AGE SEETA BE 5X

AGE OF MEETA BE 7X

AFTER TEN YEARS

AGE OF SEETA =5X+10

AGE OF MEETA =7X+10

ACCORDING TO THE QUESTION

5X+10:7X+10=7:9

=>5X+10/7X+10=7:9

CROSS MULTIPLYING  WE GET

45X+90=49X+70

20=4X

X=5

PRESENT AGE OF SEETA=5X=5*5=25

PRESENT AGE OF MEETA=7X=5*7=35

HOPE THIS HELP YOU DEAR

BYE SPREAD SMILE NOT CORONA

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