Question

9) Evaluate (3.2x^y') x (2.1x'y) when x= 1 and y = 0.5

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Answer 1

Answer:

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Let us simplify the given expression

= 3.2 x 2.1 x x6 x x² x y³ x y²

= 6.72 x x6+2 x y3+2

= 6.72x8y5

Now let us substitute when, x = 1 and y =

0.5

For 6.72x8y5

= 6.72 x 18 x 0.55

= 0.21

Answer 2

Step-by-step explanation:

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