Question

9. Find compound interest paid when a sum of 10000 is invested for 1 year and 3 months
8 per annum compounded annually.​

Answer 1

Answer:

For first year

P=10000,R=8.5%, T=1

Interest =100PRT

=100(10000×8.5×1)=850

Amount = Interest + Principle =10000+850=Rs.10850

For second year principle will be amount of previous year (since interest is compounded)

P=10850,R=8.5%, T=3months =123years=0.25years

Interest =100PRT

=100(10850×8.5×0.25)=Rs.230.5625

Total interest =850+230.5625=Rs.1080.5625

∴  Compound interest paid after 1 year and 3months is Rs.1080.5625

Step-by-step explanation:

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Answer 2

UR ANSWER:-

S.I =RS.10000

R= 8%

T= 1 YEAR AND 3 MONTHS

Step-by-step explanation:

NOW CALCULATION:--

SI.1 = 10000 x 8 x 1

___________. { for 1st year}

100

= 80000/100

= 800

Amount = P +S.I

= 10000+800

= 10800

Hence the ..

P= Rs.10800

Now..

S.I 2 = 10800 x 8 x1. { S.I FOR 3 months}

___________

100 x 3

= 108 x 8 x 1

________

3

= 36 x 8

= 288

Amount = P + S.I

= 10800 + 288

= 11088

HENCE, C.I = S.I 1 + S.I 2

= Rs. 800 + 288

= Rs. 1088