9. Find the amount to be paid at the end of 3 years in each case:
(a) Principal=*1.200 at 12% p.a. (b) Principal = 37,500 at 5% p.a.
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Answered by
0
Answer:
a) 1200 * 12 * 3 / 100 = 144 * 3 = ₹432
b) 37500 * 5 * 3/ 100 = ₹5625
Step-by-step explanation:
BRAINLIEST plz plz plz plz plz plz
Answered by
3
SOLUTION :
——————-
A) Given,
Principal/P. = Rs. 1,200
Rate/R. = 12
Time/T. = 3 years
————————————
• A = P(1+R/100) to the power n (formula)
=> A = 1200(1+12/100) to the power 3
=> A = 1200 (112/100) to the power 3
=> A = 1200*112/100*112/100*112/100
=> A = Rs. 1,685.9136
——————————————————-
B) Given,
Principal/P. = Rs. 37,500
Rate/R. = 12%
Time/T. = 3 years
—————————————
• A = P(1+R/100) to the power n (formula)
=> A = 37599(1+12/100) to the power 3
=> A = 37599(112/100) to the power 3
=> A = 37599*112/100*112/100*112/100
=> A = Rs. 52,823.8879 ( ANSWER )
———————————————————-
Hope it would help you,
Have a nice day!
:D
——————-
A) Given,
Principal/P. = Rs. 1,200
Rate/R. = 12
Time/T. = 3 years
————————————
• A = P(1+R/100) to the power n (formula)
=> A = 1200(1+12/100) to the power 3
=> A = 1200 (112/100) to the power 3
=> A = 1200*112/100*112/100*112/100
=> A = Rs. 1,685.9136
——————————————————-
B) Given,
Principal/P. = Rs. 37,500
Rate/R. = 12%
Time/T. = 3 years
—————————————
• A = P(1+R/100) to the power n (formula)
=> A = 37599(1+12/100) to the power 3
=> A = 37599(112/100) to the power 3
=> A = 37599*112/100*112/100*112/100
=> A = Rs. 52,823.8879 ( ANSWER )
———————————————————-
Hope it would help you,
Have a nice day!
:D
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