Question

9 Find the distance between the parallel lines 3x – 4y +7 = 0 and
3x – 4y + 5 = 0​

Answer 1

Answer:

Given

parallel lines

3x -4y+7=0

perp length from origin

P1= 7/√(3)sq +(-4)sq

=7/5

and another line

3x-4y+5=0

P2= 5/√(3)sq+(-4)sq

=5/5

Now distance b/w parallel lines

D=P1-P2

=7/5-5/5

=2/5 units