Question

9. Find the equation of the line passing through the points (-5,7), (-5,3)​

Answer 1

Answer:

Use formula m1x2 plus m2x1 upon m1 plus m2 for value of xand m1y2 plus m2y1 upon m1 plus ➕ m2

Answer 2

The line is represented by the equation y = m x + b

m is the slope and b is the intersection of y - axis

The slope or tangent of a line is m = (y2 - y1)/(x2 - x1)

in this case m = (3 - 7)/(( 2- ( -5)) = - 4/7

the value of b:

we can use any of the two points given to calculate the value of b.

I choose the point (2,3):

3 = (-4/7 )* 2 + b

b = 3 + 8/7 = 29/7

So the line equation is:

y = (-4/7) x + 29/7

7y =-4 *x + 29

I think one can solve this problem also

by treating the tangent or slope -4/7 as the

first derivative of line function and then do the

integration.

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