Question

9. Find the largest 7-digit number that is divisible by 3331.
10. Find the smallest 6-digit number that is divisible by 436.
Simplification
You know the operations addition, subtraction, multiplica
the operation called 'of'. 12 of 1257 means 12 times of 1257
In a simplification sum, the order in which the operations
1 Of 2 Division
3 Multiplication AA
• Simplify 7829 - 15 of 50 + 25 x 132 - 2824 + 865.​

Answer 1

Answer:

Step-by-step explanation:

9.Here is the solution: - 9999999 is the largest 7 digit number which completely divisible by 3331.

One whole number is divisible by another if, after dividing, the remainder is zero.

If one whole number is divisible by another number, then the second number is a factor of the first number.

10.Smallest 6- digit no.=100000

(Divide 100000 by 436)

The remainder is 252.

Req. no= 100000+( Divisor- Remainder)

           = 100000+( 436 - 252)

           = 100000+184

           = 100184

Ans.= The smallest 6- digit no. , exactly divisible by 436 is 100184.

11.7829 - 15 × 50 ÷ 25 × 132 × 132

= 7829 - 15 × 2 × 132 × 132

= 7829 - 522720

= - 514891