Math, asked by iamhelper30, 5 months ago

9. Find the largest 7digit number that is divisible by 1331.


10/Find the smallest 6 digit number that is divisible by 436​

Answers

Answered by Pablu
0

Answer:

The largest 7 digit number that is divisible by 1331 is 9999662

The smallest 6- digit number exactly divisible by 436 is 100184.

Step-by-step explanation:

EXPLANATION TO QUESTION 9

Assuming you consider only positive numbers, the largest 7-digit number is 9,999,999, which is not divisible by 3,331 since the division 9,999,999: 3,331 gives a quotient of 3,002 and a remainder of 337.

The same is true for 9,999,998 and for 9,999,997 and so on, each one producing, when divided by 3,331, remainders 336, 335 and so on. But if you subtract 337 from 9,999,999 you obtain 9,999,999 - 337 = 9,999,662 which is divisible by 3,331. In fact, 9,999,662 : 3,331 = 3,002 with no remainder.

Therefore, you can conclude that the largest 7-digit number divisible by 3,331 is 9,999,662

EXPLANATION TO QUESTION 10

Smallest 6- digit no.=100000

(Divide 100000 by 436)

The remainder is 252.

Req. no= 100000+( Divisor- Remainder)

           = 100000+( 436 - 252)

           = 100000+184

           = 100184

The smallest 6- digit number exactly divisible by 436 is 100184.

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Answered by chaudharyparitosh013
0

Answer:

9999662 is the your ans

Step-by-step explanation:

I hope it will help you.

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