Question

the zeros of the polynomial g(x)=x^2+7x+12 are​

Answer 1

Answer:

Here goes the solution!

Given,

x2 + 7x + 12

Zeros,

x2 + 7x + 12 = 0

x2 + 4x + 3x + 12 = 0

x(x + 4) + 3(x + 4) = 0

(x + 3)(x + 4) = 0

So, x = -3, -4

verification,

Sum of roots = -b/a = -7/1 = -7

Product of roots = c/a = 12/1 = 12

Hence, proved