9
Find the radius and Centre of the circle zz-(2 + 3i)2-(2-3i)ż + 9 = 0 where z is a complex
number.
Answers
Answered by
0
Step-by-step explanation:
Given, z
z
ˉ
+(2−3i)z+(2+3i)
z
ˉ
+4=0
Here a=2−3i,
a
ˉ
=2+3i and b=4
Hence radius
=
a
a
ˉ
−b
=
(2−3i)(2+3i)−4
=3
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