Question

9. Find the value of x3 +
3x²y + + 3xy2 + y3 if x = 2 and y = 3.​

Answer 1

QUESTION:

3x²y + + 3xy2 + y3 if x = 2 and y = 3.

ANSWER:

x³ + 3x²y + 3xy² + y³ - 8

x³ + 3x²y + 3xy² + y³ - 8x+y) ³ - 8

x³ + 3x²y + 3xy² + y³ - 8x+y) ³ - 8(x+y)³ - 23

x³ + 3x²y + 3xy² + y³ - 8x+y) ³ - 8(x+y)³ - 23(x+y-2){(x+y)² + 2(x+y)+2²}

x³ + 3x²y + 3xy² + y³ - 8x+y) ³ - 8(x+y)³ - 23(x+y-2){(x+y)² + 2(x+y)+2²}(x+y-2)(x² + y² + 2x +2y +4+xy)

Answer 2

Answer:

125

Step-by-step explanation:

using identity - (x+y)³ = x³+3x²y+3xy²+y³

2³+3(2)²(3)+3(2)(3)³+3³

= (2+3)³

= (5)³

= 125