Question

9. Find the zeroes of the quadratic polynomial 6x2-3-7x and verify the relationship between the
zeroes and the coefficients of the polynomial.
(C.B.S.E. 2008)
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Answer 1

Answer:

6x²-3-7x=0

= 6x²-7x-3=0

=> 6x²-9x+2x-3=0 ( by splitting the middle terms)

=> 3x(2x-3)+1(2x-3)=0

=> (3x+1)(2x-3)=0

From 3x+1=0,

x=-1/3

From 2x-3=0,

x=3/2

Therefore, the zeros of the given polynomial are -1/3 and 3/2

Relation between zeroes and cofficients :

-1/3 + 3/2 = -7/6 = -cofficient of x/cofficient of x²

3/2 x -1/3 = -3/6= constant term/cofficient of x²