Physics, asked by meunim, 1 year ago

9. Force acting on a particle varies with time
according to the equation F = 4 t3+ 3t2 - 2t. The
change in momentum of the particle in interval
t= 1 s tot = 2 s is
(1) 19 kg m/s
(2) 29 kg m/s
(3) 9 kg m/s
(4) 24 kg m/s​

Answers

Answered by saipremnihalani
2

Answer: the answer for this is 19 i.e option a

Explanation:

We have to integrate force with respect to time

Delta p = F.T

at integration

A part come t^4 + t^3 - t^2

Therefore [2^4-1^4] +[2^3-2^3] -[2^2-1^2]

By solving this you'll get 19

Answered by muscardinus
1

Answer:

Change in momentum of the particle is 19 kg-m/s

Explanation:

Given that,

Force acting on a particle varies with time is given by :

F=4t^3+3t^2-2t

We need to find the change in momentum of the particle in interval  t= 1 s to t = 2 s. According to second law of motion :

F=\dfrac{dp}{dt}

p=\int\limits{F.dt}

p=\int\limits^2_1 {4t^3+3t^2-2t.dt}

p=t^4+t^3-t^2|_1^2

p=2^4+2^3-2^2-(1^4+1^3-1^2)

p = 19 kg-m/s

So, the change in momentum of the particle is 19 kg-m/s. Hence, this is the required solution.

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