Question

9 Fx-a) is a factor of 2x + 2ax + 5x + 10 =
find the value of a​

Answer 1

Answer:

x+a is a factor of 2x²+2ax+5x+10

therefore f(-a)=0;

substituting values,

2(-a)²+2(a)(-a)+5(-a)+10=0

2a²-2a²-5a+10=0

-5a+10=0

therefore a=2

Step-by-step explanation:

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Answer 2

Answer:

a=2

Step-by-step explanation:

Let f(x) = 2x2+2ax+5x+10

It is given that (x+a) is a factor of f(x). So, by factor theorem, f(-a) = 0.

f(-a) = 2a2-2a2-5a+10 = 0

-5a + 10 = 0

This gives, a = 2

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