Math, asked by sia42, 10 months ago

9. If 16 men can reap a field in 30 days, in how many days will 20 men reap the same field
(a) 10 days
(b) 24 days
(C) 25 days
(d) 37 days

Answers

Answered by Sauron
48

Answer:

The time required for 20 workers is 24 days. (Option b)

Step-by-step explanation:

Given :

16 men reap the field in 30 days

To find :

Days 20 men will need to reap the field

Solution :

Let the days required by 20 men be 'm'

\begin{tabular}{|c|c|c|}\cline{1-3} Men working (x) & 16 & 20 \\\cline{1-3}\ Days required (y) & 30 & m \\\cline{1-3}\end{tabular}

As the Number of workers will increase the time required to reap the field would be less. It's an Inverse Variation.

\bigstar \: \boxed{\sf{x \times y =K }}

\sf{\implies}\: 16 \times 30 = 20 \times m \\  \\ \sf{\implies}\:480 = 20m \\  \\ \sf{\implies}\:m =  \dfrac{480}{20}  \\  \\ \sf{\implies}\:m = 24

Days required by 20 workers = 24 days

\therefore The time required for 20 workers is 24 days. (Option b)

Answered by Anonymous
36

Answer:

16 men can reap a field in 30 days

obviously, we are assuming equal strength of each man

Now 1 man can reap a field in (30×16) days

[As Same amount of work is to be done by 1 man]

1 man can reap a field in 480 days

So,20 men can reap a field in 480/20

[ As Same amount of work would be distributed among 20 men]

= 24 days

So, option b) 24 days is correct

#answerwithquality #BAL

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