Question

9. If the box of apples cost Rs (2x+3). What is the cost of (7x+3) boxes of apples

Answer 1

Answer:14x^2 + 27x +9

Step-by-step explanation:

Cost of one box = (2x+3)

Cost of (7x+3) boxes =(7x+3) * (2x+3)

=7x *(2x+3) + 3 *(2x+3)

=14x^2 +21x + 6x + 9

=14x^2 + 27x + 9

Answer 2

If a box of apples cost Rs (2x + 3) then the cost of (7x + 3) boxes of apples = 14x² + 27x + 9

Given :

A box of apples cost Rs (2x + 3)

To find :

The cost of (7x + 3) boxes of apples

Solution :

Step 1 of 2 :

Write down the cost of one box of apples

A box of apples cost Rs (2x + 3)

Step 2 of 2 :

Find the cost of (7x + 3) boxes of apples

The cost of (7x + 3) boxes of apples

= Cost of one box apple × Number of boxes

$\sf = Rs. \:(2x + 3) \times (7x + 3)$

$\sf = Rs. \:2x \times (7x + 3)+ 3 \times (7x + 3)$

$\sf = Rs. \:(14 {x}^{2} + 6x + 21x + 9)$

$\sf = Rs. \:(14 {x}^{2} + 27x + 9)$