Question

9. In a GP; a= 9 and r =-1/3 then find a
GP: a5​

Answer 1

hope this answer will be helpful ^_^

Answer 2

Answer:

1 / 9

Step-by-step explanation:

Given :

a = 9

r = - 1 / 3

We know G.P. follow as :

a , a r , a r² , a r³

G.P. = 9 , 9 × - 1 / 3 , 9 × 1 / 9 , 9 × - 1 / 27

G.P. = 9 , - 3 ,  1 , - 1 / 3.

We have term formula :

$\display \text{a _n = an ^{n-1} }\\\\\\\display \text{a _5 = 9\times-1/3 ^{5-1} }$

a_5 = 1 / 9