9 in bracket X + y whole square - x square
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aklove:
(a+b)²=a²+b²+2ab ka formula use karke x+y ko expand karo aur 9 se multiply then subtract
Answers
Answered by
66
Hi there !!
Here's your answer
Given,
to factorise 9(x + y)² - x²
It is clearly seen that the identity
a²-b²= (a - b)(a + b) will be used
where,
a = 3(x + y) , since square root of nine is 3 and square root of (x + y)² is x + y
b = x since square root of x² is x
So,
9(x + y)² - x² = (3(x + y))² - (x)²
= (3(x + y) - x )(3(x + y) + x)
= ( 3x + 3y - x)( 3x + 3y + x)
= ( 2x + 3y)( 4x + 3y ) is the answer
Here's your answer
Given,
to factorise 9(x + y)² - x²
It is clearly seen that the identity
a²-b²= (a - b)(a + b) will be used
where,
a = 3(x + y) , since square root of nine is 3 and square root of (x + y)² is x + y
b = x since square root of x² is x
So,
9(x + y)² - x² = (3(x + y))² - (x)²
= (3(x + y) - x )(3(x + y) + x)
= ( 3x + 3y - x)( 3x + 3y + x)
= ( 2x + 3y)( 4x + 3y ) is the answer
:-)
do brainliest it if helped :-)
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