Question

9. In the figures given alongside, 'A' shows a cell in the
normal state and 'B' shows the same cell after
leaving it in a certain solution for a few minutes :
A
(0) Describe the change which has occurred in the
cell as seen in B. ul locomus semouyor
(ii) Give the technical terms for the condition of the
N AS
cell as reached in B and as it was in A.
A
(iii) Define the process which led to this condition. Con
(iv) Was the solution isotonic, hypotonic or
hypertonic in which the cell was kept ? typudonia
(v) How can the cell in 'B', be brought back to its
original condition ? ​

Answer 1

Explanation:

(i) Exosmosis (exit of water) has resulted in the shrinkage of the protoplasm of cell B.

(ii) Plasmolysis and deplasmolysis.

(iii) When plant cells are kept in a hypertonic solution, exosmosis takes place. This process is called plasmolysis.

(iv) Hypertonic solution.

(v) The cell in B can be brought back to its original condition by placing it in a drop of distilled water.

(vi) 1. Cell wall, 2. Plasma membrane, 3. Chloroplast.