9. In the given Fig. 7.32, find the length of AD.
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in right angled triangle ADB,
side 1²+ side 2²=hypotenuse ²
AD²+BD²=AB²
AD²+(1.25)²=1²
AD²+1.5625=1
AD²=1-1.5625
AD²=0.5625
AD=√0.5625
AD=0.75cm
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