Question

9.
In which of the following reactions there is no change in valency
(a) 4 KCIO, → 3KCIO. + KCI
(b) SO 2 + 2H2S → 24,0 + 3S
(c) BaO + H2SO4 + BaSO4 + H 20,
(d) 2 BaO +0, + 2 BaO,​

Answer 1

Explanation:

in third reaction there is no change in valency.

Answer 2

Answer:

Concept:

A chemical reaction occurs in which one set of chemical compounds is converted into some other set of chemical compounds. Chemical reactions are defined as changes in electron positions during the development and breakdown of chemical ionic bonds, with no change in the nuclei (no change in the elements that are present), and can be expressed using a chemical equation. Nuclear chemistry is a branch of chemistry that deals with chemical interactions involving hazardous and radioactive elements that can result in both electromagnetic and nuclear alterations.

Given:

There is no change in valency in which of the following reactions?

(a) 4 KCIO, → 3KCIO. + KCI

(b) SO 2 + 2H2S → 24,0 + 3S

(c) BaO₂ + H₂SO₄ ⟶ BaSO₄ + H₂O₂

(d) 2 BaO +0, + 2 BaO

Find:

find the correct option for the given question

Answer:

The correct option is [C]

$BaO_{2} +H_{2}SO_{4} - > BaSO_{4}+H_{2}O_{2}$

As we all know, the oxygen in peroxide undergoes type 1 oxidation.

SO,

$BaO_{2}$ and $H_{2} O_{2}$

In oxygen, are peroxide has one oxidation

During the reaction, none of the responding species experience any changes in O.N. As a result, it's impossible to categorise it as a redox reaction.

A redox reaction is not a double displacement reaction. This is because in a double displacement reaction, two ionic species interact to produce products, and there is no loss or gain of electrons.

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